(3)/(2^-x)=96

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Solution for (3)/(2^-x)=96 equation: 



(3)/(2^-x)=96

We move all terms to the left:

(3)/(2^-x)-(96)=0



Domain of the equation: (2^-x)!=0

x∈R



We multiply all the terms by the denominator


-96*(2^-x)+3=0

We multiply parentheses

96x+3-=0

We add all the numbers together, and all the variables

96x=0

x=0/96

x=0

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